0.0072v^2+0.9v=38

Solution for 0.0072v^2+0.9v=38 equation:

0.0072v^2+0.9v=38

We move all terms to the left:

0.0072v^2+0.9v-(38)=0

a = 0.0072; b = 0.9; c = -38;
Δ = b2-4ac
Δ = 0.92-4·0.0072·(-38)
Δ = 1.9044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.9)-\sqrt{1.9044}}{2*0.0072}=\frac{-0.9-\sqrt{1.9044}}{0.0144}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.9)+\sqrt{1.9044}}{2*0.0072}=\frac{-0.9+\sqrt{1.9044}}{0.0144}
$